(2x^2)+5x+2=5

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Solution for (2x^2)+5x+2=5 equation:


Simplifying
(2x2) + 5x + 2 = 5

Reorder the terms:
2 + 5x + (2x2) = 5

Solving
2 + 5x + (2x2) = 5

Solving for variable 'x'.

Reorder the terms:
2 + -5 + 5x + (2x2) = 5 + -5

Combine like terms: 2 + -5 = -3
-3 + 5x + (2x2) = 5 + -5

Combine like terms: 5 + -5 = 0
-3 + 5x + (2x2) = 0

Factor a trinomial.
(-3 + -1x)(1 + -2x) = 0

Subproblem 1

Set the factor '(-3 + -1x)' equal to zero and attempt to solve: Simplifying -3 + -1x = 0 Solving -3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1x = 0 + 3 -1x = 0 + 3 Combine like terms: 0 + 3 = 3 -1x = 3 Divide each side by '-1'. x = -3 Simplifying x = -3

Subproblem 2

Set the factor '(1 + -2x)' equal to zero and attempt to solve: Simplifying 1 + -2x = 0 Solving 1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2x = 0 + -1 -2x = 0 + -1 Combine like terms: 0 + -1 = -1 -2x = -1 Divide each side by '-2'. x = 0.5 Simplifying x = 0.5

Solution

x = {-3, 0.5}

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